Class-VI NCERT Mathematics Solutions: Exercise 1.2

Q-1: A book exhibition was held for four days in a school. The number of tickets sold at the counter on the first, second, third and final day was respectively 1094, 1812, 2050 and 2751. Find the total number of tickets sold on all four days.

Solution:

Number of tickets sold on 1st day = 1094

Number of tickets sold on 2nd day = 1812

Number of tickets sold on 3rd day = 2050

Number of tickets sold on 4th day = 2751

Total tickets sold on all four days = 1094 + 1812 + 2050 + 2751 = 7707 tickets

Q-2: Shekhar is a famous cricket player. He has so far scored 6980 runs in test matches. He wishes to complete 10,000 runs. How many more runs does he need?

Solution:

Shekhar scored = 6,980

He wishes to complete = 10,000

More runs required to complete 10,000 = 10,000 – 6,980 = 3,020

Shekhar needs 3,020 more runs to score.

Q-3: In an election, the successful candidate registered 5,77,500 votes, and his nearest rival secured 3,48,700 votes. By what margin did the successful candidate win the election?

Solution:

No. of votes secured by the successful candidate = 5,77,500

No. of votes secured by his rival = 3,48,700

Margin by which he won the election = 5,77,500 – 3,48,700 = 2,28,800 votes

$\therefore$ The successful candidate won the election by 2,28,800 votes.

Q-4: Kirti bookstore sold books worth Rs 2,85,891 in the first week of June and books worth Rs 4,00,768 in the second week of the month. How much was the sale for the two weeks together? In which week was the sale greater and by how much?

Solution:

Price of books sold in week 1 = Rs 2,85,891

Price of books sold in week 2 = Rs 4,00,768

Total sales = Week 1 sales + Week 2 sales = Rs 2,85,891 + Rs 4,00,768 = Rs 6,86,659

The sale of books is the highest in the second week.

Difference in sales = Week 2 sales – Week 1 sales = Rs 4,00,768 – Rs 2,85,891 = Rs 1,14,877

Sales in week 2 is greater than sales in week 1 by Rs 1,14,877.

Q-5: Find the difference between the greatest and the least 5-digit number that can be written using the digits 6, 2, 7, 4, and 3 each only once.

Solution:

Given digits are 6, 2, 7, 4, 3

Greatest 5-digit number = 76432

Least 5-digit number = 23467

Difference between the two numbers = 76432 – 23467 = 52965

∴ The difference between the two numbers is 52965.

Q-6: A machine, on average, manufactures 2,825 screws a day. How many screws did it produce in the month of January 2006?

Solution:

Screws manufactured in a day = 2825

Number of days in January month = 31

The number of screws manufactured in January 2006 = 31 × 2825 = 87,575

Q-7: A merchant had Rs 78,592 with her. She placed an order for purchasing 40 radio sets at Rs 1200 each. How much money will remain with her after the purchase?

Solution:

Total money with Merchant = Rs 78,592

Order placed by Merchant = 40 radio sets

Cost of each radio set = Rs 1,200

So, cost of 40 radio sets = Rs 1,200 × 40 = Rs 48,000

Money left with the merchant = Rs 78,592 – Rs 48,000 = Rs 30,592

Hence, money left with the merchant after purchasing radio sets is Rs 30,592.

Q-8: A student multiplied 7236 by 65 instead of multiplying by 56. By how much was his answer greater than the correct answer?

Solution:

Incorrect product = $7236\times 65 = 469340$

Correct product = $7236\times 56 = 405216$

Difference between the incorrect and correct products = 469340 – 405216 = 64124

Therefore, the answer was greater by 64124.

Q-9: To stitch a shirt, 2 m 15 cm cloth is needed. Out of 40 m cloth, how many shirts can be stitched and how much cloth will remain?

Solution:

Total length of the cloth = 40 m = 40 × 100 cm = 4000 cm

Cloth required to stitch one shirt = 2 m 15 cm = 2 × 100 + 15 cm = 215 cm

Number of shirts that can be stitched using 4000 cm cloth = $\cfrac{4000}{215}$ = 18 shirts

Hence, 18 shirts can be stitched out of 40 m, and 1 m 30 cm of cloth is left.

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